Here's figure A since it got cut off

Mathematics

1 answer:

maw [93]2 years ago

7 0

Reflect A over the y axis. then rotate 90° counterclockwise. then translate 2 left.

You might be interested in

P² 13p=-30 menentukan nilai p

garri49 [273]

I hope this helps you

4 0

3 years ago

Brainliest for help! <br> Sketch a graph of the function <br> y =sin(x) + 2

diamong [38]

Answer:

The parent sine graph $y=sin(x)$ has a range of -1 ≤ y ≤ 1

It crosses the x-axis x = 0° ± 180°n

The maximum points occur when x = 90° ± 360°n and y = 1

The minimum points occur when x = 270° ± 360°n and y = -1

The sketch the graph of function $y=sin(x)+2$ we simply move the graph of $y=sin(x)$ up 2 units.

So this means it will have a range of 1 ≤ y ≤ 3

It no longer crosses the x-axis.

The maximum points occur when x = 90° ± 360°n and y = 3

The minimum points occur when x = 270° ± 360°n and y = 1

<u>Attached diagram</u>

The parent function $y=sin(x)$ is shown in grey (dashed line)

The function $y=sin(x)+2$ is shown in red.

4 0

2 years ago

Evaluate 4y when y = 5

Darina [25.2K]

Step-by-step explanation:

4 (5)

4×5

y=20

Hope its helpfulllll

3 0

2 years ago

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$