Answer:
25 cm^2
Step-by-step explanation:
The side length of square 1 is sqrt(169) = 13
The side length of square 2 is 48/4 = 12
From the Pythagorean Triple 13 - 12 - 5, the side length of square 3 is 5
Finally, 5 * 5 is 25
Answer:
x + 0.15x = OP
Step-by-step explanation:
OP= Original Price
(a) x = 4
First, let's calculate the area of the path as a function of x. You have two paths, one of them is 8 ft long by x ft wide, the other is 16 ft long by x ft wide. Let's express that as an equation to start with.
A = 8x + 16x
A = 24x
But the two paths overlap, so the actual area covered will smaller. The area of overlap is a square that's x ft by x ft. And the above equation counts that area twice. So let's modify the equation by subtracting x^2. So:
A = 24x - x^2
Now since we want to cover 80 square feet, let's set A to 80. 80 = 24x - x^2
Finally, let's make this into a regular quadratic equation and find the roots.
80 = 24x - x^2
0 = 24x - x^2 - 80
-x^2 + 24x - 80 = 0
Using the quadratic formula, you can easily determine the roots to be x = 4, or x = 20.
Of those two possible solutions, only the x=4 value is reasonable for the desired objective.
(b) There were 2 possible roots, being 4 and 20. Both of those values, when substituted into the formula 24x - x^2, return a value of 80. But the idea of a path being 20 feet wide is rather silly given the constraints of the plot of land being only 8 ft by 16 ft. So the width of the path has to be less than 8 ft (the length of the smallest dimension of the plot of land). Therefore the value of 4 is the most appropriate.
Answer:
Step-by-step explanation:
Quadrilaterals are four sided shapes. A parallelogram is a quadrilateral with equal and parallel opposite sides. The sum of the interior angles of any quadrilateral is always 360 degrees
Considering the question being asked, the correct option is
1) The sum of the interior angles will still be 360°. This will always remain the same no matter what type of quadrilateral is formed.
For the other options, some will remain the same and this depends on the type of quadrilateral that is formed.