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insens350 [35]
3 years ago
5

9. In the figure below, the area of Square 1 is

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

25 cm^2

Step-by-step explanation:

The side length of square 1 is sqrt(169) = 13

The side length of square 2 is 48/4 = 12

From the Pythagorean Triple 13 - 12 - 5, the side length of square 3 is 5

Finally, 5 * 5 is 25

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Answer:

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Step-by-step explanation:

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By definition of secants;

\sec \theta = \frac{1}{\cos \theta}

Now, first find the cosine of angle \theta

As the point (12 , -9) lies in the IV quadrant , where \cos \theta > 0

Consider a right angle triangle;

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Using Pythagoras theorem;

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Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

\cos \theta = \frac{Adjacent side}{Hypotenuse side}

then;

\cos \theta = \frac{12}{15} = \frac{4}{5}

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therefore, the value of \sec \theta is, \frac{5}{4}

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Answer:

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