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3 years ago

I need help on the problem!! please

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer:

choice 2) 1/4(n - 64)

Step-by-step explanation:

1/4n - 16 = 1/4(n - 64)

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Researchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a rando

inysia [295]

Answer:

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

D) The data come from a Population that is Normally distributed

F) the samples are independent

c)

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Step-by-step explanation:

Given data Among the 530 males surveyed, 175 responded "Yes

The sample proportion of males

$p_{m} ^{-} = \frac{x}{n} = \frac{175}{530} = 0.3301$

The sample proportion of 575 Females surveyed, 218 responded "Yes

$p_{fem} ^{-} = \frac{x}{n} = \frac{218}{575} = 0.3791$

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

The data come from a Population that is normally distributed.

The two samples are independent

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

We will use two samples Z - hypothesis test

$Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{p_{m}(1-p_{m}) }{n_{m} }+\frac{p_{fem} (1-p_{fem} )}{n_{fem} } }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301) }{530 }+\frac{0.3791(1-0.3791)}{575} }$

$Se(p_{m} ^{-} - p^{-} _{fem} ) = \sqrt{0.000826} = 0.0287$

The test statistic

$Z = \frac{0.3301-0.3791}{0.02875}$

Z = -1.7043

|Z| = |-1.7043|

The tabulated value Z₀.₉₅ = 1.96

The calculated Z= 1.7043 < 1.96 at 0.05 level of significance

The null hypothesis is accepted

Conclusion:-

The evidence suggest not a higher proportion of females are annoyed by this behavior

4 0

3 years ago

5.975 x 1024 plsss solve it

Mumz [18]

The answer will be 6118.4

4 0

3 years ago

By selling old CD Sarah has a store credit of $153 a new CD cost $18 what are the problem numbers of new cCD Sarah can buy

DiKsa [7]

Rileyflipflop, $\frac{153}{18}$ = 8 $\frac{1}{2}$ , since she can't buy half a CD, she's limited to no more than 8 CDs. If x = the cost of one CD, then x CDs cost $18x. Since we are limited to $153, our equation looks like... 18x < 153x < 8 $\frac{1}{2}$ Again, since we can't buy half a CD, your answer should actually be... x ≤ 8 since we can buy 8 CDs or fewer.

4 0

4 years ago

Aman left one-half of her property to his daughter, one-third to his son and donated the rest to an educational institute. If th

shutvik [7]

Answer:

Rs 600,000

Step-by-step explanation:

Let the original amount be X

Amount given to daughter = (1/2) X = X/2

Amount given to son = (1/3) X = X/3

donation = Rs 100,000

Total amount = Amount Given to Daughter + Amount given to Son + Donation

X = X/2 + X/3 + 100,000 (solve for X)

X = (5/6)X + 100,000

X - (5/6)X = 100,000

(1/6)X = 100,000

X = (6) (100,000)

x = Rs 600,000

6 0

4 years ago

What is 347,982 rounded to the nearest ten thousand

aleksandrvk [35]

347,982 rounded to the nearest ten thousand is 350,000. 40,000 is the ten thousand place and 7 is greater than five so 40,000 becomes 50,000.
Hope this helps!

3 0

4 years ago

I need help on the problem!! please ​

I need help on the problem!! please