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Darina [25.2K]
4 years ago
11

The equation 4 (x - 2) = 100 is a true equation for a particular value of x. Explain why 2 (x - 2) = 50 is also true for the sam

e value of x.​
Mathematics
1 answer:
fenix001 [56]4 years ago
7 0

Answer:

Step-by-step explanation:

i. 4 (x - 2) = 100

x-2= 100/4

x-2=25

x=25+2

x=27

ii. 2 (x - 2) = 50

x-2= 50/2

x-2=25

x=25+2

x=27

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Alexxandr [17]

Answer:

2F + 4R = 16

Step-by-step explanation:

F: no. of ferris wheel rides

R: no. of roller coaster rides

2F + 4R = 16

4 0
3 years ago
Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3
enot [183]

Answer:

y = (x - 3)^2 - 12

(3,-12)

Step-by-step explanation:

Given

y = x^2 - 6x - 3

Solving (a): In vertex form

The vertex form of an equation is:

y = a(x - h)^2 + k

To do this, we make use of completing the square method.

We have:

y = x^2 - 6x - 3

------------------------------------------------------------------

Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

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y = x^2 - 6x - 3

y = x^2 - 6x + 9 - 9 - 3

y = x^2 - 6x + 9 - 12

Factorize x^2 - 6x + 9

y = x^2 - 3x-3x + 9 - 12

y = x(x - 3)-3(x - 3) - 12

Factor out x - 3

y = (x - 3)(x - 3) - 12

Express as squares

y = (x - 3)^2 - 12

Hence, the vertex form of y = x^2 - 6x - 3 is: y = (x - 3)^2 - 12

Solving (b): State the coordinates of the vertex.

In y = a(x - h)^2 + k; the vertex is: (h,k)

The vertex of y = (x - 3)^2 - 12 will be (3,-12)

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3 years ago
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2(5)= 10ft

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fredd [130]

Answer:

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Step-by-step explanation:

hope this helps

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