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hodyreva [135]
3 years ago
11

Use compatible numbers to estimate 5320÷61

Mathematics
1 answer:
suter [353]3 years ago
5 0
Ur answer to ur division problem would be 87.2131147541
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If the perimeter of a square is 5 feet now many Inches long is each side of the square
gogolik [260]

Answer:

Well since we know that the perimeter of a square is four times the length of one of its sides. We just have to divide 5 by 4 to get the length of one side:

5feet /4 sides = 1.25 feet

And to finish off, we have to convert feet to inches:

1 foot      = 12 inches

1.25 feet    x inches

x inches = 12 inches x 1.25 feet ÷ 1 foot

x inches = 15 inches

Therefore, each side is 15 inches long.

Hope this helps!

Step-by-step explanation:

7 0
2 years ago
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Which ordered pair (x,y) satisfies the system of equations shown below? 2x-y=6 x+2y=-2 A) (-6,2) B) (-2,2) C)(2,-2) D) (4,2)
Nastasia [14]

Answer:

(-6,2) is the answer

Step-by-step explanation:

7 0
3 years ago
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Pie graphs should be used when the data is represented as a percentage.<br><br><br> True<br> False
horrorfan [7]

Answer: True

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3 0
3 years ago
Please help me anyone
kotykmax [81]

Answer:

Quelles caractéristiques ces mots ont-ils en commun ? Cliquez sur tout ce qui s'applique.

  • <u><em></em></u>\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]<u><em></em></u>

Step-by-step explanation:

8 0
2 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
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