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hodyreva [135]
3 years ago
11

Use compatible numbers to estimate 5320÷61

Mathematics
1 answer:
suter [353]3 years ago
5 0
Ur answer to ur division problem would be 87.2131147541
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Your job pays $8 per hour. (a) Write an algebraic expression for your pay in dollars for working h hours. (b) What is your pay i
Korvikt [17]
P = 8h.....where P stands for pay

if u work 36 hrs...
P = 8(36)
P = 288 <==
4 0
3 years ago
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Find the area of the shaded region
zepelin [54]

Answer:

area of a circle πr^2

r = 10/2 r = 5

π5^2 = 78.5

area of the square length X width

7 x 7 = 49

78.5 - 49 = 29.5

shaded region = 29.5 square cm

3 0
3 years ago
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Consider the intersecting lines shown. Which of the following statements is true?
elixir [45]

Answer:

C. m∠x + m∠y = 180

Step-by-step explanation:

The two straight line in the diagram intersect each other to form two pairs of vertical angles. These are <x and <z, and <y and w.

The only statement from the given options that is true is m∠x + m∠y = 180.

This is because they are angles in a straight line. The sun of angles in a straight line is 180°.

3 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Solve for h.<br>3/7 = h/14 - 2/7​
AleksAgata [21]

Answer:

10

Step-by-step explanation:

Multiplying both sides by 14

2*3=h-(2*2)

6=h-4

h=6+4

h=10

3 0
3 years ago
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