Divide 5.60 by 70 and that's the price per ounce
Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
Answer:
multiply the chances
1/2 (every other number is even right)
1/2 x 1/6 (if it is a normal dice) = 1/12
1/12 chance
Step-by-step explanation:
Answer:
There were 39 children at the party
Step-by-step explanation:
Here, we want to know the number of children at the party
To do this, we have to add the y-values ( frequencies of the age grades)
We have this as;
8 + 8 + 7 +10 + 6 = 39
