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3 years ago

. Find the measure of angle C if the area of triangle ABC (below) is 54 square inches.

Mathematics

1 answer:

Sonja [21]3 years ago

4 0

basically it is going to be 58 degrees because you actually have to add all of the degrees together.

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A new baby is born in France the newspaper reports the baby's mass to be 1.5×10³ kg

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The question only supplied us with the mass of the new baby which is:

$1.5\cdot10^3\operatorname{kg}\Rightarrow1500\operatorname{kg}$

This mass is too bizzarre & unrealistic for

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1 year ago

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5 is the answer your prop

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3 years ago

Solve the equation 2<br> 16x + 20 = 0 to the nearest tenth.

Alenkasestr [34]

Answer:

x ≈ - 1.3

Step-by-step explanation:

16x + 20 = 0

16x + 20 - 20 = 0 - 20

16x = - 20

16x ÷ 16 = - 20 ÷ 16

x = - 1.25

$x=-1\frac{1}{4}$

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3 years ago

Read 2 more answers

on a drawing, the height of a school block is 4cm. Given that the actual heigh of the block is 30m, find the scale of the drawin

Aloiza [94]

Answer:

1 cm to 7.5 m

Step-by-step explanation:

A drawing scale is a ratio of two numbers.

The given scale, 4 cm to 30 m, can be written as a ratio in the form of a fraction,

(4 cm)/(30 m)

Since it can be written as a fraction, it can also be reduced like a fraction.

The problem wants the number of cm to be 1 cm. We have 4 cm.

Divide the numerator and denominator by 4.

(1 cm)/(7.5 m)

Now write it in the format the problem asks.

1 cm to 7.5 m

3 0

2 years ago

Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the lin

Anit [1.1K]

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

$\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

Step-by-step explanation:

From the question we are told that

the given equation is

$\= r(t) = (4-3t) + (-5 + t) + (3-t)$

This given equation can be represented as

$\= r (t) = [4 -3t , -5+t,3-t]$

Generally this equation can be represented in terms of the parametric equations as follows

$\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

This above equation is obtained by assigning each component of r(t) to each line

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3 years ago