Question

If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, what is the volume of the tank? Assume 3.14 for pi. A) 28.3 m3 B) 37.7 m3 C) 56.5 m3 Eliminate D) 84.8 m3

Answer 1

Answer:

(D) $V$≈$84.8m^3$

Step-by-step explanation:

It is given that If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, thus the radius of the cylindrical tank is given as:

$Diameter=\frac{Radius}{2}=\frac{6}{2}=3m$

and the height is=6m.

Now, the volume of the cylindrical tank is given as:

$V={\pi}r^2h$

Substituting the given values, we get

$V=3.14(3)^2(3)$

$V=3.14(27)$

$V=84.78m^3$

$V$≈$84.8m^3$

Hence, the volume of the cylindrical tank is $84.8m^3$.

Thus, option D is correct.

Answer 2

For a cylindrical tank, volume = πr²h

Where r = radius = diameter/2 = 6/2 = 3m
height , h = 3m

Volume  =  3.14 * 3² * 3 = 84.78

Volume ≈ 84.8 m³

Option D.