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3 years ago

A, 25 + 7b x 9b - 83

Mathematics

1 answer:

PtichkaEL [24]3 years ago

3 0

5^2x × 7b - 9b +83
25x × 7b - 9b + 83
so c is the answer

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PLEASE ANSWER THIS

irinina [24]

Answer:

a) 1/4

b) 0.95

Step-by-step explanation:

0.25 is 25/100, which is 1/4

19/25 is 95/100, which is 0.95

3 0

3 years ago

Man borrows 26,000 for 3 years with simple interest 1.7 percent determine the amount of money repay after three years

Naya [18.7K]

Answer:

$1,326

Step-by-step explanation:

You are going to want to use the simple interest formula for this.

$I=Prt$

I = interest amount

P = principal amount

r = interest rate

t = time

First, change 1.7% into its decimal form:

1.7% -> $\frac{1.7}{100}$ -> 0.017

Next plug in the values into the equation:

$I=26,000(0.017)(3)$

$I=1,326$

After three years, he must repay $1,326.

4 0

3 years ago

If x = -2 and y = 3, by how much does 2y2 - x exceed 2x2 - y?

Akimi4 [234]

Yes it does, to find this insert the values of x and y into the equation.
14>-11

3 0

4 years ago

The ages (in years) and weights (in pounds) of all wide receivers for a football team are listed. Find the coefficient of variat

IceJOKER [234]

Answer:

The coefficient of variation for the weight and age are 5.9% and 10.6%.

Step-by-step explanation:

The coefficient of variation (CV) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is:

$CV=\frac{\sigma}{\mu}\times 100\%$

Here σ = standard deviation and µ = mean.

Compute the mean and standard deviations of the two data set in Excel using the following functions.

Mean=AVERAGE()

Standard deviation=STDEV.S()

Consider the Excel sheet attached.

The mean and standard deviation of weight are:

Mean = 202, Standard deviation = 11.87

And the mean and standard deviation of weight are:

Mean = 25.88, Standard deviation = 2.75

Compute the coefficient of variation for the weight as follows:

$CV_{weight}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{11.87}{202}\times 100\%\\\\=5.87624\\\\=5.9\%$

Compute the coefficient of variation for the age as follows:

$CV_{age}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{2.75}{25.88}\times 100\%\\\\=10.62597\\\\=10.6\%$

Thus, the coefficient of variation for the weight and age are 5.9% and 10.6%.

8 0

3 years ago

Find the values of m for which the lines y=mx-2 are tangents to the curve with equation y=x^2-4x+2

deff fn [24]

Let y= mx-2 be the tangent line to y=x^2-4x+2 at x=a.

Then slope, $m=\frac{dy}{dx} at x=a = 2a-4.$

Hence the equation is y=(2a-4)x-2

Let's find y-coordinate at x=a using tangent line and curve.

Using tangent line y at x=a is (2a-4) a -2 $=2a^{2}-4a-2$

Using given curve y-coordinate at x=a is $a^{2}-4a+2$

Let's equate these 2 y-coordinates,

$2a^{2} -4a-2 = a^{2} -4a+2$

$2a^{2}-a^{2} = 2+2$

$a^{2}=4$

a=2 or -2.

If a=2, $m=2a-4 = 2*2-4=0$

If a=-2, $m= 2(-2)-4 = -8$

Hence m values are 0 and -8.

8 0

4 years ago