Step-by-step explanation:
Answer:
Thanks
Step-by-step explanation:
Answer:
f^-1(x) is 6x + 48
f(x) = 1/6x - 8
To find f^-1(x) equate f(x) to y
That's
f(x) = y
y = 1/6x - 8
Next interchange the terms
We have
x = 1/6y - 8
Make y the subject
Multiply through by 6
We have
6x = y - 48
y = 6x + 48
Therefore f^-1(x) is 6x + 48
Hope this helps you
Complete the square of y^2 + 10y to answer this question.
x=y^2 + 10y + 22 becomes x = <em>y^2 + 10y + 100</em> - 100 + 22, or
x = (y+10)^2 - 78
Comparing this result to the generic form x = a(y-k)^2 + h, we see that
h = -78 and k = -10.
Then the vertex of this parabola is at (-78, -10).