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evablogger [386]
3 years ago
6

A jug of water is 1/3 full. If 5 children equally share the water, what fraction of the full jug does each child get?

Mathematics
2 answers:
love history [14]3 years ago
7 0
The answer would be B) 1/15 
DaniilM [7]3 years ago
3 0

Answer:

Correct option is:

B) 1/15

Step-by-step explanation:

A jug of water is 1/3 full.

5 children equally share the water

i.e. 5 children get water= 1/3 of full jug

On dividing both sides by 5, we get

1 children get water= 1/15 of full jug  

Hence, Correct option is:

B) 1/15

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
Does anyone know this ?
AnnyKZ [126]

Answer:

I think it is A, C, E I'm. it too sure, sorry if it's wrong

7 0
3 years ago
The order of magnitude for the population of the world is five. true or false?
pochemuha
The Order of magnitude for the population of the world is not five
5 0
3 years ago
Antoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.
lana66690 [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
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ASAP Help now 10 pts
Ede4ka [16]

Answer:

$6

Step-by-step explanation:

Each foot cost $2

Hope this helped!

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2 years ago
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