find the total surface area of a cylindrical candle with a diameter of 4 in and a height of 2.5 inch round to the nearest tenth

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

A= $\pi r^{2}$

A=3.14*2*2*

A=12.56

A=25.12in

A=l*w

A=4*2.5

A=10in

TSA=35.1 $in^{2}$

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