Check the picture 1.
The regions contained in an odd number of these 5 circles are
the pink colored region, contained only in the circle with radius 2,
and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.
So what we need to determine is the "area pink + area yellow".
Consider the second picture.
Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.
the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

Thus, the overall yellow region is

The purple area is:
Area of large circle - 4*(Area of 1 small circle) + yellow region.
(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

Finally, the total area is :

(units squared)
Answer:

square units