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Sav [38]
4 years ago
13

Commuters in London have the problem that buses are often already full and, therefore, cannot take any further

Mathematics
1 answer:
SVETLANKA909090 [29]4 years ago
6 0

Commuters in London have the problem that buses are often already full and, therefore, cannot take any further

passengers. Sarah is heading home from work. She has the choice of going to Bus Stop A, where there are three

buses per hour and 30% of the buses are full, or Bus Stop B, where there are four buses per hour and 40% of the

buses are full. Which stop should she choose in order to maximize the probability that she will be able to get on a

bus within the next hour? (Hint: Calculate the probability, for each bus stop, that she will fail to get on a bus within

the next hour. You may assume that the buses are full, or not, independently of each other.)

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Answer:

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4 years ago
Among 6 electrical components exactly one is known not to function properly. If 2 components are randomly selected, find the pro
Oksanka [162]

Answer:

66.67% probability that all selected components function properly

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the components are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Desired outcomes:

2 components which function properly, from a set of 5. So

D = C_{5,2} = \frac{5!}{2!(5-2)!} = 10

Total outcomes:

2 components, from a set of 6. So

T = C_{6,2} = \frac{6!}{2!(6-2)!} = 15

Probability:

p = \frac{D}{T} = \frac{10}{15} = 0.6667

66.67% probability that all selected components function properly

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