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sergiy2304 [10]
3 years ago
8

Sorry if it's hard to read {I will give brainliest and thanks)

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0
Translation of a line segment doesn't affect it's length, 'cause it has shifted from one location to another, no change in it's size.

In short, Your Answer would be Option B

Hope this helps!
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The slope of the normal curve y=3x^2-5x is at the point (0,0)
Rufina [12.5K]

Answer:

\frac{1}{5}

Step-by-step explanation:

Consider the curve y=3x^2-5x

Differentiate with respect to x

\frac{dy}{dx} =3(2x)-5=6x-5

( Use \frac{d}{dx}(x^n)=nx^{n-1} )

Slope of normal curve is given by \frac{-1}{\frac{dy}{dx} }

Slope of normal curve = \frac{-1}{6x-5}

To find slope of normal curve at point (0,0) ,put x=0 in \frac{-1}{6x-5}

Slope of normal curve at point (0,0) = \frac{-1}{6(0)-5} =\frac{-1}{-5}=\frac{1}{5}

8 0
3 years ago
-7x+12-2x=23+13x simplify by combining like terms that are on the same side of the equation
zavuch27 [327]
-7x+12-2x=23+13x

First take away 13x from the right side and put it on the left side adding taking it away from -7x 

-7x(-13x)=-20x
-20x+12-2x=23

then add 2x to -20x
and move 12 to the other side, minus it off of 23

-18x=11

then divide -18x on both sides 

then x=-11/18

6 0
4 years ago
Describe the TRANSFORMATIONS below. * f(x)= (x-6)²+4
Brilliant_brown [7]

Answer:

Move right 6 units and up 4 units

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

<em>a</em> = vertical stretch/shrink

<em>b</em> = horizontal stretch/shrink

<em>h</em> = horizontal movement left/right

<em>k</em> = vertical movement up/down

5 0
3 years ago
PLEASE HELP IN IMAGE nonsense will be reported
Degger [83]
The answer is -2. The line is going from left to right which makes it negative. Then if you look at the line and do change in y(rise) over change in x(run).
8 0
3 years ago
Write in simplest form ::: 12c - c
Tomtit [17]
The answer for your question is 11c. The reason why it's actually 11c is because 12c - c equals 11c.

Hope this helps:)
7 0
3 years ago
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