Last time I checked that was about right, but it's been a few years since then.
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer:
C
Step-by-step explanation:
If the number's a fraction, which this one is, the denominator will always be that little number by the radical, and the whole number will be in the root. Hope this helps!
Option B: 5 is the value of f(3)
Explanation:
The equation of the piecewise function is given by

We need to find the value of 
The value of the function f can be determined when
by identifying in which interval does the value of
lie in the piecewise function.
Thus,
lies in the interval
, the function f is given by

Substituting
in the function
, we get,


Thus, the value of
is 5.
Therefore, Option B is the correct answer.
Answer:
i can't see it was blur
i can't answer can you pic it again