Is 39500 one hundred times 3950?

Solve the equation for y 4x+7y=28 y=

bogdanovich [222]

Let's solve for y.

4x+7y=28

Add -4x to both sides.

4x+7y+−4x=28+−4x

7y=−4x+28

Divide both sides by 7.

7y/7=−4x+28/7

y=−4/7x+4

5 0

2 years ago

Solve the equatuon x/2-(2/(x+1))=1 x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$

Thus, the answer is x = 3, -2

7 0

2 years ago

Watch help video If you place a 13-foot ladder against the top of a 12-foot building, how many feet will the bottom of the ladde

riadik2000 [5.3K]

$\begin{gathered} X\text{ will represent the bottom of the ladder fom the bottom of the building} \\ U\text{sing pythagoras Theorem} \\ (Hyp)^2=(opp)^2+(Adj)^2 \\ 13^2=x^2+12^2 \\ 169=x^2\text{ +144} \\ 169-144=x^2 \\ 25=x^2 \\ x^2\text{ = 25} \\ x\text{ = }\sqrt[]{25} \\ x\text{ = 5foot} \end{gathered}$

6 0

7 months ago

Segment lm is the midsegment of trapezoid abcd. ab = 58, and dc = 98. what is lm?

kifflom [539]

Lm would be 78 because it is halfway between ab and dc and 98-58=40 and half of 40=20, so 58+20=78 or 98-20=78.

3 0

3 years ago

WILL GIVE BRAINLIEST

Evgesh-ka [11]

All you have to do is plug in the given values into the given equation and evaluate.

The expression is,

$A(t) = l{e}^{rt}$
But we have to analyze the problem carefully. This is a natural phenomenon that can be modelled by a decay function. The reason is that, after every hour we expect the medicine in the blood to keep reducing.

Therefore we use the decay function rather. This is given by,

$A(t) = l{e}^{-rt}$

where,

$l = 100 \: milligrams$

$r = \frac{14}{100} = 0.14$

and

$t = 10 \: hours$

On substitution, we obtain;

$A(10) = 100 \times {e}^{ - 0.14 \times 10}$

$A(10) = 100 \times {e}^{ - 1.4}$

Now, we take our calculators and look for the constant
$e$

,then type e raised to exponent of -1.4. If you are using a scientific or programmable calculator you will find this constant as a secondary function. Remember it is the base of the Natural logarithm.

If everything goes well, you should obtain;

$A(10) = 100 \times 0.24659639$

This implies that,

$A(10) = 24.66$

Therefore after 10 hours 24.66 mg of the medicine will still remain in the system.

3 0

2 years ago