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melisa1 [442]
3 years ago
10

A cylinder has a radius of 6 centimeters and a height of 18 centimeters. A smaller cylinder has linear dimensions that are one-t

hird the dimensions of the larger cylinder. Compare the surface area of the smaller cylinder to the surface area of the larger cylinder.
Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

Answer:

the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.

Step-by-step explanation:

Surface area of larger cyclinder

Radius = 6cm

Height = 18cm

A = 2πrh + 2πr^2

= 2*3.14*6*18 + 2*3.14*6^2

= 678.24 + 226.08

= 904.32 cm

Smaller cyclinder (1/3 of the larger cyclinder)

Radius = 2cm

Height = 6cm

A = 2πrh + 2πr^2

= 2*3.14*2*6 + 2*3.14*2^2

= 75.36 + 25.12

= 100.48 cm

Comparing the surface area of the larger cyclinder and the smaller cyclinder

= 904.32 cm / 100.48 cm

= 9

This means, the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.

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3 years ago
A rectangular rug has a perimeter of 220 feet. The width of the rug is two feet less than the length. Find the length and the wi
Gekata [30.6K]

Answer:

The length is 56 and the width is 54.

Step-by-step explanation:

The perimeter of a rectangle is 2x+2y (width and length on both sides). so 2x+2y=220. Also x=y-2, because the width is 2 feet less than the length. Fill x=y-2 in 2x+2y=220 and we get 2(y-2)+2y=220. 2y-4+2y=220. 4y=216. y=54. Fill in y=54 in 2x+2y=220 and we get 2x+2(54)=220. 2x=220-2(54)=112. x=56.

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3 years ago
Please help me.i don't get it.
alukav5142 [94]

Answer:

See below.

Step-by-step explanation:

The addition method is a good choice in this case since you have x in one equation and -x in the other equation, and x and -x add to zero, eliminating x.

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Add the equations. x and -x ad to zero, eliminating x. Then solve for y.

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Divide both sides by -2.9

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Solution: x = -3; y = 2

Since the coefficients of y in the two original equations are not opposites, the addition method would not be the best method to use to solve for y first.

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