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3 years ago

Some please help me out ASAP !!!!

Mathematics

1 answer:

VMariaS [17]3 years ago

8 0

Answer:

About 3

Step-by-step explanation:

Since all real life objects have three dimensions, if you increase the dimensions of an object by a certain factor, the object's volume is greater by the factor cubed.

1500*x^3=45000

x^3=30

x is about 3

Hope this helps!

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Andre took 6 kicks and made 4 goals: 4 out of six. Tom wants to take more than 20 kicks and make a equivalent fraction to Andre.

Zanzabum

Answer:

Tom can either take 24 kicks and make 16 goals or 30 kicks and make 20 goals.

Step-by-step explanation:

Andre made 4 goals out of 6 kicks.

Tom wants to take more than 20 kicks and to make an equivalent fraction to Andre.

Possibility 1:

Let Tom makes 24 kicks.

To get 24, we need to multiply the denominator of Andre's fraction by 4.

So, $\frac{4}{6} =\frac{16}{24}$

Therefore, Tom can take 24 kicks and make 16 goals.

Possibility 2:

Let Tom makes 30 kicks.

To get 30, we need to multiply the denominator of Andre's fraction by 5.

So, $\frac{4}{6} =\frac{20}{30}$

Therefore, Tom can take 30 kicks and make 20 goals.

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2 years ago

Simplify the expression. Write answer using only positive exponents. (1/3a^3)^-4

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Answer:

81/a^12

Step-by-step explanation:

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2 years ago

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Lera25 [3.4K]

Answer:

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2 years ago

Robert says 12 divide by 3//4 = 9. He used the following steps: 12/1 × 3/4 = 36/4 What error did Robert make? A. Robert used sub

wlad13 [49]

Answer:

C and D are the same answers but one of those.

Step-by-step explanation:

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2 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

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2 years ago