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Hunter-Best [27]
3 years ago
14

Some please help me out ASAP !!!!

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0

Answer:

About 3

Step-by-step explanation:

Since all real life objects have three dimensions, if you increase the dimensions of an object by a certain factor, the object's volume is greater by the factor cubed.

1500*x^3=45000

x^3=30

x is about 3

Hope this helps!

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Pleasee mwa mwa mwa help me
sammy [17]

Answer: About (-2.414, 0) and (0.414, 0)

Step-by-step explanation:

       Let us graph the equation given and see what the x-intercepts are. These are points where the line intercepts the x-axis. <em>See attached</em>.

       This means our x-intercepts are at about (-2.414, 0) and (0.414, 0).

                        These are also equal to -1-\sqrt{2} and  -1+\sqrt{2}

8 0
1 year ago
Read 2 more answers
Helppppppppppppppppppppppppp
Akimi4 [234]
1. x <= 31
2. x < 28

For number 1, x is less than or equal to 31 because the number of days in a month (represented by x) will be less than or equal to 31.

For number 2, x is less than 28 because the number of students (represented by x) in each class will always be less than 28.
7 0
3 years ago
Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A
ser-zykov [4K]

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

6 0
3 years ago
Which of the following is a valid exclusion for the algebraic fraction 8ab^2x/4a^2b - 8ab^2
avanturin [10]

The valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b

<h3>How to determine the valid exclusion?</h3>

The expression is given as:

8ab^2x/4a^2b - 8ab^2

Set the denominator to 0

4a^2b - 8ab^2 = 0

Divide through by 4ab

a - 2b = 0

Add 2b to both sides

a = 2b

Hence, the valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b

Read more about algebraic fraction at:

brainly.com/question/4344214

#SPJ1

7 0
1 year ago
If you work 8 hours every two days, how many hours will he work in 7 days
zubka84 [21]

Answer:

28 hours for 7 days

Step-by-step explanation:

8/2 =

4

4 hours for 1 day

1 x 7 =

7

7 x 4

28

28 for 7 days

6 0
2 years ago
Read 2 more answers
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