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trasher [3.6K]
2 years ago
6

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?

Chemistry
1 answer:
saveliy_v [14]2 years ago
8 0

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

A hydrocarbon would be an organic molecule in organic chemistry that is made completely of hydrogen as well as carbon. A good example of group 14 hydrides includes hydrocarbons. In general, hydrocarbons lack color and are hydrophobic. Typically, their faint smells are compared to that of gasoline and lighter fluid.

  • The longest unbroken carbon chain should be found and named.
  • Name the groups that make up this chain but instead identify them.
  • Beginning at the end of the chain closest to a substituent group, fraction the chain sequentially.
  • Give each substituent group a corresponding number but also name to indicate its placement.

Therefore, according to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

To know more about hydrocarbon

brainly.com/question/12433190

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4 years ago
At 35°C, Kc = 1.6 multiplied by10-5 for the following reaction
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Answer : The equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

Explanation : Given,

Moles of  NO = 2 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NO = 2 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                            2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Initial conc.          2 M            1 M            0

At eqm. conc.    (2-2x) M   (1-x) M         (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NOCl]^2}{[NO]^2[Cl_2]}

The K_c for reverse reaction = \frac{1}{1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

\frac{1}{1.6\times 10^{-5}}=\frac{(2x)^2}{(2-2x)^2\times (1-x)}

By solving the term 'x', we get :

x = 0.975

Thus, the concentrations of NO,Cl_2\text{ and }NOCl at equilibrium are :

Concentration of NO = (2-2x) M  = (2 - 2 × 0.975) M = 0.05 M

Concentration of Cl_2 = (1-x) M = 1 - 0.975 = 0.043 M

Concentration of NOCl = x M = 0.975 M

Therefore, the equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

6 0
3 years ago
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Irina-Kira [14]

Answer:

The answer is the same as .

Explanation:

There are 3 atoms in NaOH, 1 sodium, 1 oxygen and 1 hydrogen.

There are 3 atoms in H2O, 2 hydrogen and 1 oxygen.

3 0
3 years ago
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