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3 years ago

A machine at Staples photocopies 12 ¼ pages per minute. If the machine runs 700 minutes, how many pages will be photocopied?

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

8 0

8575 copies will be copied

Kaylis [27]3 years ago

4 0

The machine will make 8575 photocopies

You might be interested in

Dos numeros naturales se diferencian en 7 unidades y la suma de sus cuadrados es 289

NeTakaya

Answer:

15 y 8

Step-by-step explanation:

y = x - 7

x² + y² = 289

sustituir: x² + (x - 7)² = 289

distribuir: x² + x² - 14x + 49 = 289

sustraer + simplificar: 2x² - 14x - 240 = 0

dividir: x² - 7x - 120 = 0

x² - 15x + 8x - 120 = 0

(x - 15)(x + 8) = 0

x = 15, x = -8 --> x ≠ -8 porque -8 no es naturales

sustituir: y = 15 - 7

simplificar: y = 8

6 0

2 years ago

Alexis received an 85, 89, and 92 on three tests. How many points does she need to score on her next test in order to have an av

Tpy6a [65]

Alexis needs to score at least 96 points on her next test in order to have an average of at least 90.

explanation:
85+89+92+96= 360
359/4=90

6 0

3 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

Two of them are drawn simultaneously from a deck of 48 cards.

Elina [12.6K]

The required probability is
a) both are cups is 0.05

b) At least one cup is 0.19

c) One is a cup and the other is a sword is 0.06

<h3 /><h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

a) for both are cups

P= 12*11/48*47
p = 0.05

b) for At least one cup
p = 12*36/48*47
p = 0.19

c) for One is a cup and the other is a sword
p = 12*12/48*47
p = 0.06

Thus, the required probability is 0.05, 0.19, 0.06

Learn more about probability here:

brainly.com/question/14290572

6 0

1 year ago

A baker uses 2.327 kilograms of blueberries for muffins. There are four packages at the fruit market. Which amount is closest to

irinina [24]

Answer:

2.33 kg

Step-by-step explanation:

If the baker needs to use 2.327 kilograms of blueberries, we are going to subtract the amount of the packages to the amount he needs and we'll see which is the smallest number.

In the case of 2.3, 2.327 - 2.3 = .027

In the case of 2.42, 2.327 - 2.42 = -0.09

In the case of 2.33, 2.327 - 2.33 = -0.003

In the case of 2.4, 2.327 - 2.4 = -0.07

Therefore, the closest amount to 2.327 is the 2.33 package.

4 0

2 years ago