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kolezko [41]
2 years ago
11

Apply properties of operatione to write an equivalent expression​

Mathematics
1 answer:
____ [38]2 years ago
4 0

Answer:

4t

Step-by-step explanation:

All we are doing is combining like terms and since all of then have a "t" in it we would just add the 4 "t's" together like normal addition.

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8x-19=-3x-41
+3x +3x
11x-19=-41
+19 +19
11x=-22
÷11 ÷11
x=-2
8 0
3 years ago
What type of number is 3/2
garri49 [273]

Answer:

it is a mixed number the number is 1 1/2

Step-by-step explanation:

6 0
2 years ago
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Find the <br> (D)<br> (R)<br> &amp;<br> (A)
omeli [17]
<h3>Answer: Choice C</h3>
  • domain = (-infinity, infinity)
  • range = (-infinity, 0)
  • horizontal asymptote is y = 0

========================================================

Explanation:

Since no division by zero errors are possible, and other domain restricting events are possible, we can plug in any x value we want. This means the domain is the set of all real numbers. Representing this in interval notation would be (-infinity, infinity).

The range is the set of negative real numbers, which when written in interval notation would be (-infinity, 0). This is because y = 5^x has a range of positive real numbers, and it flips when we negate the 5^x term. The graph of y = -5^x extends forever downward, and the upper limit is y = 0.

It never reaches y = 0 itself, so this is the horizontal asymptote. Think of it like an electric fence you can get closer to but can't touch.

7 0
3 years ago
Leah and Junko share a reward of $81, in a ratio 1:8. How much does Junko get?
Marina CMI [18]

Answer:

Junk gets 72

Step-by-step explanation:

Leah: Junko: total

1            8         1+8 = 9

The total is 81

81/9 = 9

Multiply each part by 9

Leah: Junko: total

1*9         8*9    9*9

9             72    81

5 0
2 years ago
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Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
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