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3 years ago

Work out the area of a trainable of base 6cm and height 8cm

Mathematics

1 answer:

docker41 [41]3 years ago

8 0

6 times 8=48/2=24 cm squared
You divide by two because there are two triangles in a square.

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What is the range for this set of data? 7,15,12

shtirl [24]

To find the range of data, you first order the data least to greatest:
7, 12, 15
Then you subtract the smallest number from the largest:
15-7=8

The range is 8.

5 0

4 years ago

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<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%28190%29%5E%7B3%7D%20%7B68%5E%7B2%7D%20%7D%20%20%5Ctimes%20%28%20%5Cfr

mrs_skeptik [129]

Answer:

$\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}$

Step-by-step explanation:

The applicable rules of exponents are ...

(ab)^c = (a^c)(b^c)

(a^b)/(a^c) = a^(b-c)

$\dfrac{190^3}{68^2}\times\dfrac{34}{95^{\frac{19}{3}}}=\dfrac{(2\cdot 95)^3}{(2\cdot 34)^2}\cdot\dfrac{34}{95^6\cdot 95^{\frac{1}{3}}}=2^{3-2}95^{3-6-\frac{1}{3}}34^{1-2}\\\\=2\cdot 95^{-3\frac{1}{3}}\cdot 34^{-1}=2\cdot 95^{-4+\frac{2}{3}}\cdot 34^{-1}\\\\=\dfrac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}$

6 0

3 years ago

Find the length of x round your answer to the nearest hundredth

allsm [11]

Answer:

x = 7.55

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 +b^2 = c^2

where a and b are the legs and c is the hypotenuse

a^2 +8^2 = 11^2

x^2 +64 = 121

Subtract 64 from each side

x^2 +64-64 = 121-64

x^2 =57

Take the square root of each side

sqrt(x^2) = sqrt(57)

x = 7.549834435

To the nearest hundredth

x = 7.55

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3 years ago

The table shows the results for spinning the spinner 75 times what is the related frequency for the event spin a 2

arsen [322]

Answer:

8/25 it the answer

Step-by-step explanation:

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3 years ago

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What is 1.086 rounded to the nearest whole number

Sphinxa [80]

1.086 rounded to the nearest whole number is 1

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3 years ago