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2 years ago

Pls help me no one helps me

Mathematics

2 answers:

Anettt [7]2 years ago

7 0

Answer:

2/45

Step-by-step explanation:

Jlenok [28]2 years ago

5 0

2/45 I think let’s hope I’m not wrong

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ΔCDE is reflected over the x-axis. What are the vertices of ΔC'D'E' ?

sattari [20]

Answer:

Step-by-step explanation:

When reflecting over the x-axis:

(x, y) (x, -y)

The y changes signs (+, -)

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2 years ago

The bees buzzed by the beatiuful blue bag, what is this?

11111nata11111 [884]

Alliteration

how I remember is that the 2 L’s are together in the word, and the same letter is repeated in the sentence.
if that makes sense,

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3 years ago

Read 2 more answers

if alyssa plans to run 7/8 mile on a trail at one point she sees that she is at mile maker 0.3 How much farther does she have to

Sever21 [200]

Rewrite 7/8 as a decimal by dividing 7 by 8:

7/8 = 0.875

Now to find how much further she has to run subtract where is now from the total distance:

0.875 - 0.3 = 0.575

She needs to run 0.575 miles more

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2 years ago

The linear function graphed below represents the value of a comic book since Lucy purchased it. What was the value of the comic

zhuklara [117]

Answer:

C. $25

Step-by-step explanation:

We will find,

The slope of the function using $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .

Taking the points (1,40) and (2,55).

Slope = $\frac{55-40}{2-1}$

i.e. Slope = $\frac{15}{1}$

i.e. Slope = 15

Substituting the slope and point (1,40) in the equation $y=mx+b$ ,

We have, $40=15\times 1+b$

i.e. $b=40-15$

i.e. b= 25

Thus, the equation of the linear function is $y=15x+25$ .

<em>This linear function represents the cost of the comic book since Lucy purchased it, where x= years.</em>

So, the initial value of the comic book is when x= 0.

So, $y=15\times 0+25$ i.e. y= 25

Hence, the cost of the book when Lucy purchased it was $25.

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3 years ago

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Which answer is equivalent to<br> ??? Help please

grigory [225]

Answer:

$\large\boxed{\dfrac{36}{25}}$

Step-by-step explanation:

$\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}$

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3 years ago