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Sladkaya [172]
3 years ago
10

bsmiddle" class="latex-formula">
identify any domain restrictions
Mathematics
1 answer:
ruslelena [56]3 years ago
6 0
x\in \mathbb{R}
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Llana [10]

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Step-by-step explanation:

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For (x)=3x+1 and g(x)=x^2 -6, find (f+g)(x)
julsineya [31]

Answer:

<h2>(f + g)(x) = x² + 3x - 5</h2>

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=3x+1;\ g(x)=x^2-6\\\\(f+g)(x)=(3x+1)+(x^2-6)=x^2+3x+1-6=x^2+3x-5

4 0
3 years ago
If the equation of a circle is (x - 2)2 + (y-6)2 = 4, it passes through point
san4es73 [151]

(x - 2)² + (y - 6)² = 4

You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point

Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)

So alternative b.

To be more certain just subs the point in the x and y, if its equal, it pass through

(x - 2)² + (y - 6)² = 4

To point (4, 6)

(4 - 2)² + (6 - 6)² = 4

(2²) + 0² = 4

4 = 4

Thats right

4 0
3 years ago
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