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dlinn [17]
3 years ago
5

Question 3 of 10

Mathematics
1 answer:
katovenus [111]3 years ago
8 0

Answer:

No solution

Step-by-step explanation:

Not sure tbh

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1. Find m
Bess [88]
It's forming a circle so we know that together it's going to add up to 360. #1 is 66 because angle A trough E is straight and we have 90 on angle ACF and it's vertical to angle FCG. #2 is 125 because angle ACB is 24 because it's vertical to angle GCE. #3 is 114 because 90 and 24 is 114. #4 is 156 because 66 and 90 equal 156.
1. FCG = 66
2. BCD = 125
3. FCB = 114
4. ACG = 156
4 0
3 years ago
Write the pair of fractions as a pair of fractions with a common denominator 1/2 and 1/3
ICE Princess25 [194]

Answer:

1/6? it has the common denominator

6 0
3 years ago
Read 2 more answers
I need help not good at graphs
Charra [1.4K]

Answer:

a, b

Step-by-step explanation:

a and b  cause  all  the data are  not in a form of a line

6 0
3 years ago
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Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)=\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)=\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}

6 0
2 years ago
the store has 28 notebooks in packs of 4. three packs of nitebooks are sold. how many packs of notebooks are left?
ICE Princess25 [194]
There are 4 note books left. Hope this helps :)
7 0
3 years ago
Read 2 more answers
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