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igor_vitrenko [27]
3 years ago
6

The equation below shows the relationship between the number of apples purchased, a, and the total cost

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
The answer is c! $4.00
inessss [21]3 years ago
6 0

Answer:

C

Step-by-step explanation:

a (5) = c (4)

5 x 4 = 20

20 (total) divided by the 5 apples is $4.

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Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

7 0
3 years ago
Read 2 more answers
A wheel assembly is
Basile [38]

Answer:

The total weight of the assembly is 7 pounds.

Step-by-step explanation:

The total weight of the assembry is found by the sum of the weights of each components.

We have:

2 wheels, each weighing 2.6 pounds, so 2*2.6 = 5.2 pounds

An axle, which weighs 1.8 pounds, so 5.2+1.8 = 7 pounds

The total weight of the assembly is 7 pounds.

5 0
3 years ago
What is the slope of the line that passes through (3,-7) and (-1,1)
mafiozo [28]

the slope would be the change in Y over the change in X,

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3 0
3 years ago
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The symbol above represents the principle of yin and yang, one of the main concepts in Chinese philosophy. What does the concept
alukav5142 [94]
It represents the<u> balance of opposites</u> and The existence of evil. 
6 0
3 years ago
Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
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