-33 2/3
dsanndsvnnvlkjsdkvnsdkjlfnjndsfjkjdslfjsdkfkjlhldskjfbsdlkjfkjbvbjkdbfjbnjdsbfjbfd
I had to add more
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
x= -8 and so y=35.....solving equation
Answer:
option ;
Step-by-step explanation:
Answer:
m<HGI=21°
Step-by-step explanation:
we know that
If GH bisects m<FGI then
m<FGH=m<HGI
substitute the values
(2x+1)°=(3x-9)°
solve for x
3x-2x=1+9
x=10°
The measure of angle HGI is equal to
(3x-9)° ------> substitute the value of x
3*10-9=21°
m<HGI=21°