if we do a <u>vertical line test</u> on that graph, we'll find that a vertical line will pass by and hit the line only once on its way down, only once meaning the graph is the graph of a function.
<h2>Range</h2>
well, is really how high and low it goes or namely over the y-axis.
well, it goes up up up to 3 then U-turns and back down it goes, now the graph has arrowheads, meaning the graph keeps on going towards infinity, vertically as well as horizontally since it's a parabola, so the range will be
<h2>[3 , +∞)</h2>
<h2>Domain</h2>
well, is simply how left and right it goes or namely over the x-axis.
judging from the arrowheads it moves from infinity to infinity, so
<h2>(-∞ , +∞).</h2>
First I calculate in how many weeks Caroline will get 80$
4$*20 weeks =80$
but Caroline had 20$ at the beginning which means in 20 weeks she will have collected 80$+ 20$= 100$
the answer is after 20 weeks Caroline will have more than 100$in her bank .
Answer: Y = 3/4x + 3
Step-by-step explanation:
If two lines are perpendicular, then the product of the two slopes should be -1.
First change 4x + 3y = 7 to Slope intercept form
(4x - 4x) + 3y = 7 - 4x
3y/3 = 7/3 - 4/3x
Y = -4/3x + 7/3 ( -4/3 is the slope)
Then find the slope of line n
-4/3 x S = -1
(-3/4 x -4/3) x S = -1 x -3/4
S = 3/4
Slope of line n is 3/4
Next find the Y-intercept of line n
Since line n contains (2,3) we can use 3 as the y-intercept of line n
Hence, the equation of line n is Y = 3/4x + 3
9514 1404 393
Answer:
≈ (3.578, 5.789)
Step-by-step explanation:
We can substitute for y and solve for x.
(x -h)^2 +(y -k)^2 = r^2 . . . equation of a circle with center (h, k), radius r
x^2 +(y -4)^2 = 4^2 . . . . . . the equation of the given circle
x^2 +((0.5x +4) -4)^2 = 16
(5/4)x^2 = 16
x = 8/5√5 . . . . multiply by 4/5 and take the square root
y = 0.5x +4
y = 4/5√5 +4
The point of intersection is (8/5√5, 4+4/5√5), approximately (3.578, 5.789).
Answer:
B. If an object is dropped from a height of 38 feet, the function h(t) = –16t2 + 38 gives the height of the object after t seconds.
Step-by-step explanation:
The equation that models the movement of the object is:
Where,
t: time
a: acceleration due to gravity
v0: initial speed
h0: initial height
Suppose that the object falls with zero initial velocity and from a height of 38 feet.
The equation that models the problem is:
Answer:
If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds
Answer: If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds
Step-by-step explanation:
