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nikitadnepr [17]
3 years ago
10

Circle O is shown. Secants C A and C E intersect at point C outside of the circle to form an angle with measure 36 degrees. Seca

nt C A intersects the circle at point B, and secant C E intersects the circle at point D. Arc B D is 48 degrees. In circle O, what is mArc A E?
Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0

Answer:

<h2>120°</h2>

Step-by-step explanation:

The external angle <C outside the circle can be expressed in terms of length of arc AE and BD using the formula below.

<C = \frac{AE-BD}{2} \\

Next is to make the length of arc AE the subject of the formula;

<C = \frac{AE-BD}{2} \\

cross multiply

2

add BD to both sides of the equation

2

AE = 2

Given

<C = 36°

arc BD = 48°

Substitute the given parameters into the formula;

AE = 2

Hence mArc is 120°

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Step-by-step explanation:

<h2><u>Definition of terms:</u></h2>

The general form of an absolute function is given by: y = a|x - h| + k, where:

| <em>a </em>| ⇒ Determines the vertical <em>stretch</em> or <em>compression</em> factor of the function.

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In terms of the <u>vertex,</u> it occurs at point, (2, 3), where <em>h</em> = 2, and <em>k</em> = 3.  

Therefore, the vertex of the given absolute value function is (2, 3).

8 0
3 years ago
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