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patriot [66]
3 years ago
10

How many g i2 should be added to 750g ccl4 to prepare a 0.200m solution?

Chemistry
2 answers:
vesna_86 [32]3 years ago
6 0
<span>There are a number of ways to express concentration of a solution. This includes molality. Molality is expressed as the number of moles of solute per mass of the solvent. We calculate as follows:

0.200 mol I2 / kg CCl4 ( .750 kg CCl4 ) ( 253.809 g I2 / mol I2) = 38.07 g I2 needed

Hope this helps.

 </span>
tamaranim1 [39]3 years ago
3 0

Answer:

Mass of I2 required = 38.1 g

Explanation:

<u>Given:</u>

Mass of CCl4 = 750 g = 0.750 kg

Molality of the solution = 0.200 m

<u>To determine:</u>

Mass of I2

<u>Formula:</u>

Molality of a solution is expressed as the ratio of the amount of solute per kg of solvent

Molality = \frac{moles\ of\ solute}{kg\ solvent} \\

Here the solute is I2 and solvent is CCl4

Moles\ of\ I2 = molality*mass\ solvent = 0.200*0.750= 0.150 moles\\\\Molar\  mass\  of\  I2 = 253.8 g/mol\\\\Mass\ of\ I2 = moles*molar\ mass = 0.150*253.8 = 38.1 g

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