Question

How many g i2 should be added to 750g ccl4 to prepare a 0.200m solution?

Answer 1

There are a number of ways to express concentration of a solution. This includes molality. Molality is expressed as the number of moles of solute per mass of the solvent. We calculate as follows:

0.200 mol I2 / kg CCl4 ( .750 kg CCl4 ) ( 253.809 g I2 / mol I2) = 38.07 g I2 needed

Hope this helps.

 

Answer 2

Answer:

Mass of I2 required = 38.1 g

Explanation:

Given:

Mass of CCl4 = 750 g = 0.750 kg

Molality of the solution = 0.200 m

To determine:

Mass of I2

Formula:

Molality of a solution is expressed as the ratio of the amount of solute per kg of solvent

$Molality = \frac{moles\ of\ solute}{kg\ solvent}$

Here the solute is I2 and solvent is CCl4

$Moles\ of\ I2 = molality*mass\ solvent = 0.200*0.750= 0.150 moles\\\\Molar\ mass\ of\ I2 = 253.8 g/mol\\\\Mass\ of\ I2 = moles*molar\ mass = 0.150*253.8 = 38.1 g$