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Chemistry

1 answer:

Vladimir79 [104]3 years ago

8 0

Answer:

please only post questions if you actually need it.

Explanation:

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A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$