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3 years ago

8

Please work out all the problems on this page, no links, no i don't knows please do not take advantage of me or my points please

actually answer these questions

2 answers:

Ymorist [56]3 years ago

5 0

2nd option: they move more freely

ArbitrLikvidat [17]3 years ago

4 0

Answer:

Explanation:

2nd

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3 years ago

Công thức của A có dạng Ca(hco3)x có ptk là 162 tìm x

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2 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

True [87]

First, in order to calculate the specific heat capacity of the metal in help in identifying it, we must find the heat absorbed by the calorimeter using:
Energy = mass * specific heat capacity * change in temperature
Q = 250 * 1.035 * (11.08 - 10)
Q = 279.45 cal/g

Next, we use the same formula for the metal as the heat absorbed by the calorimeter is equal to the heal released by the metal.

-279.45 = 50 * c * (11.08 - 45) [minus sign added as energy released]
c = 0.165

The specific heat capacity of the metal is 0.165 cal/gC

6 0

3 years ago

Read 2 more answers

Which types of atomic orbitals of the central atom mix to form hybrid orbitals in:<br> (b) CS₂;

Anettt [7]

<u>One s orbital</u> and <u>one p orbital</u> are the exact types of atomic orbitals of the central atom mix to form hybrid orbitals in CS₂

<h3>What is atomic orbital?</h3>

An atomic orbital is a function used in atomic theory and quantum mechanics to explain the position and wave-like behaviour of an electron in an atom. This function can be used to determine the likelihood of discovering any atom's electron in any particular area surrounding the nucleus.

The physical area or space where the electron may be calculated to be present, as predicted by the specific mathematical shape of the orbital, is referred to as an atomic orbital.

The three quantum numbers n, l, and $m_l$ which correspond to the electron's energy, angular momentum, and an angular momentum vector component, are used to describe all orbitals in an atom (magnetic quantum number).

Learn more about Atomic Orbital

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6 0

1 year ago

In reality, a hydrate of iron(III) nitrate had to be used, not the anhydrous salt. As you may guess, some of the hydrate’s mass

liq [111]

<u>Answer:</u> The mass of nonahydrate iron (III) nitrate is 16.2 g

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Fe(NO_3)_3$ = 0.0020 M

Volume of solution = 2 L

Putting values in above equation, we get:

$0.0200M=\frac{\text{Moles of }Fe(NO_3)_3}{2L}\\\\\text{Moles of }Fe(NO_3)_3=(0.0200mol/L\times 2L)=0.04mol$

The chemical equation for the decomposition of hydrated iron (III) nitrate follows:

$Fe(NO_3)_3.9H_2O\rightarrow Fe(NO_3)_3+9H_2O$

By Stoichiometry of the reaction:

1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate

So, 0.04 moles of iron (III) nitrate will be produced from = $\frac{1}{1}\times 0.04=0.04mol$ of hydrated iron (III) nitrate

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol

Moles of nonahydrate iron (III) nitrate = 0.04 moles

Putting values in above equation, we get:

$0.04mol=\frac{\text{Mass of nonahydrate iron (III) nitrate}}{404.0g/mol}\\\\\text{Mass of nonahydrate iron (III) nitrate}=(0.04mol\times 404.0g/mol)=16.2g$

Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g

7 0

2 years ago