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ArbitrLikvidat [17]
2 years ago
5

A composite figure is formed by combining a square and a triangle. Its total area is 52.5 ft. The area of the

Mathematics
1 answer:
otez555 [7]2 years ago
3 0

The length of each side of the square is 3 ft.

<u>Step-by-step explanation:</u>

We have , A composite figure is formed by combining a square and a triangle. Its total area is 52.5 ft. The area of the  triangle is 43.5 ft . We know that area of a square = length^{2} . According to question:

area of square = length^{2}

area of triangle = 43.5 ft

total area = 52.5 ft.

Total area = area(square+triangle)

⇒ 43.5 + (Length)^{2} = 52.5

⇒ (Length)^{2} = 52.5- 43.5

⇒ (Length)^{2} = 9

⇒ (Length) = \sqrt{9}

⇒ Length= 3

Therefore, the length of each side of the square is 3 ft.

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Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

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Where;

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For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

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The length of segment P'R' = √10

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Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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