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slavikrds [6]
2 years ago
8

Tommy travel 495 miles at 45 mi/hr. How long did the trip take ?

Mathematics
2 answers:
givi [52]2 years ago
8 0

Answer:

D

Step-by-step explanation:

495 / 45 = 11 hours

Option D

BigorU [14]2 years ago
4 0

Answer:

11 hours

Step-by-step explanation:

Simply divide 495 miles / 45 miles traveled per hour

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The answer is the graph will be 3 units to the left
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Illusion [34]
I’m not sure but maybe true
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Can I have somebody answer a few more of the questions that I need please and this one too?
tankabanditka [31]

Answer:

x > 22

Step-by-step explanation:

<em>Hey there!</em>

Well to solve,

52 - 3x < -14

we need to single out  x

52 - 3x < -14

-52 to both sides

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Divide both sides by -3

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The < changes to > because the variable number is a - being divided.

<em>Hope this helps :)</em>

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4 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
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