Based on the right angle triangle and the given parameters, cos K = 5/13
<h3>Trigonometric ratios</h3>
- sin = opposite / hypotenuse
- cos = adjacent / hypotenuse
- Tan = opposite / adjacent
Given parameters:
- Hypotenuse = 13
- Adjacent = 5
- Opposite = 12
Therefore,
cos K = adjacent / hypotenuse
cos K = 5/13
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Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
Answer:
x-y=4
Step-by-step explanation:
(y+4)/(1+4) = x/5
(y+4)/5 = x/5
y+4 = x
-x+y= -4
x-y = 4
Answer:
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