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andrew-mc [135]
4 years ago
7

Solve 4(2x - 1) - 3 = 9(x - 4) answers -29 32 13 29

Mathematics
1 answer:
Nikitich [7]4 years ago
7 0
Try using Socratic it’s amazing
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What is the distance between the points (7,-6) and (13,2)? Please show all work.
lana [24]

Answer:

Step-by-step explanation:

(7,-6) (13,2)

2--6. 8. 4

------= ------= ------ (2--6 turns to a +)

13-7. 6. 3

4

Slope:------

3

Points=(7,-6)

4

y--6=----(x-7) (y--6 turns to a +)

3

4. 28

y+6= ---- x - ----

3. 3

-6. -6

-------------------------

4. 46

y=----- x - -------

3. 3

6 0
3 years ago
What is the slope of the line that contains the points (-1, 8) and (2, -4)?
trapecia [35]

Answer:

-4

Step-by-step explanation:

The slope of a line given two points is given by

m = (y2-y1)/(x2-x1)

   = (-4-8)/(2 - -1)

   = (-4-8)/(2+1)

   = -12/3

   = -4

4 0
4 years ago
Read 2 more answers
PLEASE HELP -7y + 11 = 75 + y
Masja [62]

Answer:

y = -8

Step-by-step explanation:

-7y + 11 = 75 + y

Bring the <em>"</em><em>y</em><em>"</em><em> </em>variable on one side, and rest on the other.

Rearranging, we get,

-7y - y = 75 - 11

-8y = 64

-y = 8

y = -8

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

3 0
2 years ago
in Cranston taxis charge $4 plus $0.90 per mile for an airport pickup how far from the airport can Ralph travel for $17.50​
Mrac [35]

Answer:

14.4444 miles

Step-by-step explanation:

y=4+0.9x

plug in 17.5 for y

then solve

8 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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