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3 years ago

The length of a rectangle is (8x – 9) and the width is (2x + 3).

Mathematics

1 answer:

love history [14]3 years ago

6 0

Answer:

P = 20x - 12

Step-by-step explanation:

The Perimeter of a Rectangle is 2l + 2w, where l is the length and w is the width.

Now, let's substitute the given values.

2(8x - 9) + 2(2x + 3)

= 16x - 18 + 4x + 6

= 20x - 12 <--- This is the answer

Hope this helps!

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Juan brought 4 Tshirts and leather jacket. The T shirts were all the same price, and the price of the leather jacket was 6 times

Alex

Let us say that:

x = the number of T shirts bought = 4

y = the number of leather jackets bought = 1

a = the price of the T shirts

b = the price of the leather jackets

With the given variables, we can say that the total cost is:

total cost = a x + b y

Since, b = 6 a, therefore:

total cost = a x + 6 a y

total cost = a (x + 6 y)

Since total cost is 209, therefore we can calculate for a since x and y are also given:

209 = a (4 + 6 * 1)

209 = a (10)

a = $20.9

Therefore each T shirt cost $20.9

7 0

3 years ago

Pete borrowed $400 for 1 year. He paid back a total of $440. What was the interest rate per year?

OleMash [197]

I=PRT/100

1. Make R (rate) subject

R/100= I/PT

2. Substitute and calculate

r/100= i/pt

r/100= 40/400 × 1

(40 is from 440-400.The interest)

r/100= 0.1

r/100×100= 0.1×100

r=10% (interest rate per year)

To confirm

I=PRT

I= 400×10/100×1

I= $40 (Interest)

5 0

3 years ago

Read 2 more answers

Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (

aleksley [76]

Answer:

$H_0: p = 0.5\\H_a: p \neq 0.5$

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test

x = 56

n = 100

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{56}{100}$

$\widehat{p}=0.56$

Formula of test statistic = $\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

= $\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}$

= $1.2$

refer the z table for p value

p value = 0.8849

a. We get 560 heads out of 1000 tosses.

We will use one sample proportion test

x = 560

n = 1000

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{560}{1000}$

$\widehat{p}=0.56$

Formula of test statistic = $\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

= $\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}$

= $3.794$

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

6 0

2 years ago

Please help +25 points

mestny [16]

The answer is D.
Hope I helped

8 0

2 years ago

OC and OR are similar. Find the length of QP.

Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is $s = \frac{22 \pi}{9}$

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s, r and $\theta$ is

$arclength = 2\pi r \frac{\theta}{360}$

where,

s be the length of the arc

r be the radius

$\theta$ be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

$2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}$

or, $2r \frac{\theta}{360} = \frac{22}{9}$ [ eliminating $\theta$ from both side]

or, $\theta = \frac{(22)(360)}{(9)(2)(4)}$

or, $\theta = 110^\circ$

Again,

For circle R

Taking, r = 6 and $\theta = 110^\circ$ we get,

The length of arc QP is

$arc length = 2\pi (6)(\frac{110}{360} )$

or, $arclength = \frac{11 \pi}{3}$

Hence,

The length of QP is $\frac{11 \pi}{3}$ . Option C.

5 0

3 years ago