All categories

3 years ago

Find the slope of everyline that is perpendicular to the graph of the equation y-2/3x=2

Mathematics

1 answer:

Flauer [41]3 years ago

3 0

Answer:

m= -3/2

Step-by-step explanation:

First, we must find the slope of the line given. We are given the equation:

y-2/3x=2

We must get this equation in slope-intercept form: y=mx+b (where m is the slope and b is the y-intercept). In order to do this, we must get y isolated.

2/3x is being subtracted from y. We want to preform the inverse, so we should add 2/3x to both sides.

y-2/3x+2/3x=2+2/3x

y=2+2/3x

Rearrange the terms.

y= 2/3x+2

Now the equation is in slope intercept form. (y=mx+b). 2/3 and x are being multiplied, so we know that the slope is 2/3.

Now, we have to find the perpendicular slope. Perpendicular lines have negative reciprocal slopes.

1. Negative

m=2/3

Negate the slope.

m= -2/3

2. Reciprocal

m= -2/3

Flip the numerator (top number) and denominator (bottom number).

m= -3/2

The perpendicular slope is -3/2

You might be interested in

A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per

ivanzaharov [21]

2 m/s²

Step-by-step explanation:

Step 1:

Let the initial velocity be 0 m/s and the final velocity be 8 m/s and the time traveled is 4 s.

From the basic science,

Acceleration = ( Final Velocity - Initial Velocity) / Time

Step 2:

Acceleration = (8-0)/4

2 m/s²

4 0

4 years ago

30 points pls help quick

AVprozaik [17]

X+2y=5
-x+3y=6
Answer: (-3, 4)

x+2(0)=5
x=5

(0)+2y=5
y=5/2

-x+3y=6
Answer: x-intercept: A. y-intercept: C.
(-6,2)

Not sure, here though.

3 0

2 years ago

Plz plz plz plz plz plz find x

Nuetrik [128]

Answer:

36 i think

Step-by-step explanation:

6 0

3 years ago

I dont understand this

Westkost [7]

Answer:

$\dfrac{1}{2x(x-1)}$

Step-by-step explanation:

Given

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)$

Consider the numerator:

$x^2+2x+1=(x+1)^2$

Consider the denominator:

$x^2-1=(x-1)(x+1)$

Hence, the fraction becomes

$\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}$

Consider the expression in brackets:

$2x^2+2x=2x(x+1)$

Divide:

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}$

4 0

3 years ago

Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW

valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

$\frac{a}{sin78}$ = $\frac{18}{sin53}$ ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = $\frac{18sin78}{sin53}$ ≈ 22.0 ( to the nearest tenth )

(3)

$\frac{c}{sinC}$ = $\frac{a}{sinA}$ , substitute values

$\frac{35}{sinC}$ = $\frac{45}{sin134}$ ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = $\frac{35sin134}{45}$ , then

∠ C = $sin^{-1}$ ( $\frac{35sin134}{45}$ ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values

$\frac{BC}{sin38}$ = $\frac{10}{sin50}$ ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = $\frac{10sin38}{sin50}$ ≈ 8.0 ( to the nearest tenth )

3 0

3 years ago