i would say B
when it says "the measure", it's refering to where the second quartile is beginning
Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:

648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then

There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651
Answer:
That is correct.
Step-by-step explanation:
2 times 10=20
4 times 1=4
5 times 0.1=0.5
8 times 0.01=0.08
20+4+0.5+0.08=24.58
That is correct.
Answer:not sure what u talking about
Step-by-step explanation:
Answer:
19.25
Step-by-step explanation: