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lara31 [8.8K]
3 years ago
9

EASY POINTS FOR YOU!!! :)

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

C. 20 cm

Step-by-step explanation:

kvasek [131]3 years ago
7 0

Answer:

20 cm

Step-by-step explanation:

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a cuboid with a volume of 924 cm3 has dimensions 4cm (x+1)cm and (x+11)cm. show clearly that x^2 +12x-220=0. show the equation b
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Answer:

Part 1)

The equation by factorization is

x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))

Both values of x are

x1=-6+\sqrt{266}

x2=-6-\sqrt{266}

Part 2) The dimensions of the cuboid are

4\ cm, (-5+\sqrt{266})\ cm and (5+\sqrt{266})\ cm

Step-by-step explanation:

step 1

we know that

The volume of the cuboid is equal to

V=LWH

substitute the given values

V=4(x+1)(x+11)

V=924\ cm^{3}

so

4(x+1)(x+11)=924\\4(x^{2}+11x+x+11)=924\\ 4(x^{2}+12x+11)=924\\x^{2}+12x+11=231\\x^{2}+12x-230=0

Complete the square

x^{2}+12x-230=0

x^{2}+12x=230

x^{2}+12x+36=230+36

(x+6)^{2}=266

square root both sides

x+6=(+/-)\sqrt{266}

x=-6(+/-)\sqrt{266}

so

x1=-6+\sqrt{266}

x2=-6-\sqrt{266}

therefore

The equation by factorization is

x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))

step 2

Find the dimensions of the cuboid

The dimensions are

4\ cm

(x+1)\ cm -----> (-6+\sqrt{266}+1)=(-5+\sqrt{266})\ cm

(x+11)\ cm ----> (-6+\sqrt{266}+11)=(5+\sqrt{266})\ cm

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