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garik1379 [7]
3 years ago
14

Tim had 187 dollars to spend on 9 books. After buying them he had 16 dollars. How each book cost

Mathematics
2 answers:
-Dominant- [34]3 years ago
4 0

the answer is 19 because 187 - 16 = 171 divided 9 = 19


Charra [1.4K]3 years ago
3 0

187-16= 171

171 / 9= 19

The books were $19 dollars each.

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During a bike challenge riders have to collect various colored ribbons each half mile they collect a red ribbon each 8th mile th
soldi70 [24.7K]

Answer:

Green and Blue ribbon

Step-by-step explanation:

Given

They collect

Red Ribbon = ½ mile

Green Ribbon = ⅛ mile

Blue Ribbon = ¼ mile

To find?

Which colors of ribbons will be collected at the ¾ mile mark.

The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.

Testing each fraction.

Red Ribbon = ½

¾ ÷ ½

= ¾ * 2

= 3/2

= 1.5 or 1 Remainder 1

This is not an exact multiple of ¾. So, the red ribbon won't be passed here.

Green Ribbon = ⅛

¾ ÷ ⅛

= ¾ * 8

= 24/8

= 3

This is an exact multiple of ¾. So, the green ribbon will be collected.

Testing the last ribbon

Blue = ¼

¾ ÷ ¼

= ¾ * 4

= 3

This is an exact multiple of ¾. So, the blue ribbon will be collected.

Hence, the green and blue ribbons will be collected at ¾ mile mark

3 0
3 years ago
Please answer this for me correctly I am new to brain.ly and thanks! :)
77julia77 [94]
B. You're welcome sis
4 0
3 years ago
Read 2 more answers
What’s the first 1st term in the sequence given by :T(n)=n^2-4<br> Pls help
Zepler [3.9K]

First term = T(1) is obtained by plugging  n = 1 into the formula,

thus First term = 1^2 - 4 = 1 - 4

= 3    (answer)

8 0
3 years ago
A soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while
bija089 [108]

Answer:

The probability that the assembly line will be shut down is 0.00617.

Step-by-step explanation:

We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.

Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.

Let X = <u><em>Number of bottles in the sample that are not within specification</em></u>.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....

where, n = number of trials (samples) taken = 12 bottles

             x = number of success  = 2 or more bottles

            p = probabilitiy of success which in our question is probability that  

                 bottles are not within specification, i.e. p = 0.01

So, X ~ Binom (n = 12, p = 0.01)

Now, the probability that the assembly line will be shut down is given by = P(X \geq 2)

  P(X \geq 2) = 1 - P(X = 0) - P(X = 1)

                 = 1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}

                 = 1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})

                 = <u>0.00617</u>

8 0
3 years ago
In a class of p students, the average (arithmetic mean) of the test scores is 70. in another class of n students, the average of
lys-0071 [83]

First case:

average of test score =70

number of students =p

total score of 'p' students = ( average of test score)*( number of students)

total score of 'p' students =70p

Second case:

average of test score =92

number of students =n

total score of 'n' students = ( average of test score)*( number of students)

total score of 'n' students =92n

total number of students = p+n

total average score =86

so, total score =86(p+n)

total score = total score of 'p' students +total score of 'n' students

86(p+n)=70p+92n

now, we can simplify it

86p+86n=70p+92n

86p-70p=92n-86n

16p=6n

now, we can find p/n

\frac{p}{n}= \frac{6}{16}

\frac{p}{n}= \frac{3}{8}................Answer


5 0
3 years ago
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