Answer:
the
of students in the class are
students
the
of students here in class today are
Step-by-step explanation:
Let
x-------------> total students in the class
y------------- >number of the students here in class
so

we know that

the interval solution for x is all whole numbers belong to the interval
![[0,49]](https://tex.z-dn.net/?f=%5B0%2C49%5D)
the solution will be a number belonging to the interval
such that when multiplying by
it gives me a whole number
see the attached excel table
the
of students in the class are
students
the
of students here in class today are
Hello! To solve this problem, we can split the problem in two and add the products together.
5 x 3 = 15
1/3 x 3 = 0.9
15 + 0.9 = 15.9
Hope this helps! :)
Answer:
Question 1: y = 3/4x + 1/4.
Question 2: y = 6/5x + 7/5.
Step-by-step explanation:
Question 1: A line perpendicular to another line would have a slope that is the negative reciprocal of the other line. If the slope of the first line is -4/3, the slope of a line perpendicular to the first would have a slope of 3/4.
Since the line goes through (5, 4), we can just put the points into the equation, y = 3/4x + b.
4 = 3/4(5) + b
b + 15/4 = 4
b = 16/4 - 15/4
b = 1/4
So, the equation of the line is y = 3/4x + 1/4.
Question 2: 5x + 6y = -6
6y = -5x - 6
y = -5/6x - 1
As stated before, a line perpendicular to another will have a slope that is the negative reciprocal of the other. So, the slope of the other line is 6/5.
The line goes through (-2, -1), so we can put the points into the equation, y = 6/5x + b.
-1 = 6/5(-2) + b
b - 12/5 = -5/5
b = -5/5 + 12/5
b = 7/5
So, the equation of the line is y = 6/5x + 7/5.
Hope this helps!
Answer:
x = 8
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for x
The square on the hypotenuse is equal to the sum of the squares on the other two sides, thus
x² + 6² = 10²
x² + 36 = 100 ( subtract 36 from both sides )
x² = 64 ( take the square root of both sides )
x =
= 8