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alukav5142 [94]

3 years ago

11

Which graph shows y=x^2+3x-4

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

Third graph in the photo

Step-by-step explanation:

x^2+3x-4 can be factored as (x+4)(x-1). When y=0, x must be -4 or 1 to satisfy the equations, and thus the roots of the graph are at x=-4 and x=1. When x=0, y=(4)(-1)=-4. The only graph that satisfies both of these requirements is the third/last one.

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Can someone help please

Alik [6]

Answer:

6

Step-by-step explanation:

base + 2(legs) = 56 (2 legs are the same because it's isosceles)

x + 2(5x - 5) = 56

x + 10x - 10 = 56

11x -10 = 56

11x = 66

x = 6

5 0

3 years ago

The length of a rectangular is 7/10 ft .and the width is 1/5ft what is the perimeter

Blababa [14]

<h3>Answer:</h3>

$\huge\boxed{1 \frac{4}{5}\ \text{ft}}$

<h3>Explanation:</h3>

Change $\frac{1}{5}$ so that is has a common denominator. $\frac{1*2}{5*2}=\frac{2}{10}$

Make an equation. $\frac{7+7+2+2}{10}$

Add. $\frac{14+4}{10}$

Add. $\frac{18}{10}$

Divide both sides by 2. $\frac{9}{5}$

Convert to a mixed number. $1 \frac{4}{5}$

4 0

3 years ago

Read 2 more answers

Juan made 13 out of 20 free throws. If Botina shoots 25 free thows, what's the minimum number she has to make in order to have a

Dahasolnce [82]

Answer:

the answer is 17

Step-by-step explanation:

juans free throw % is 65 so botina has to make 17 out of 25 to get a better percent which is 68

7 0

3 years ago

Read 2 more answers

I need to know what’s the the length

Monica [59]

Answer:

b=4

Step-by-step explanation:

P.T.c^2=a^2 +b^2

5^2=3^2 +b^2

25=9+b^2

b^2 =25-9

b^2 =16

b=sqrt(16)

b=4

8 0

3 years ago

Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i

Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) $\frac{20i+21}{29}$

(c) i

Step-by-step explanation:

We have to perform division

(a) $\frac{1-2i}{2i}$

So after division

$\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1$

(b) We have given expression $\frac{5-2i}{5+2i}$

After rationalizing $\frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}$

(c) We have given expression $\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}$

After rationalizing

$\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i$

5 0

4 years ago