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shutvik [7]
3 years ago
14

WHAT IS 9 PLUS 10????????????? NEED HELP​

Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

19

Step-by-step explanation:

10

+9

____

19

Vera_Pavlovna [14]3 years ago
5 0

Answer:19

Step-by-step explanation:

10

9

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3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum
ivolga24 [154]

Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son     = y - 3

Then , from the first statement :

x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x     = 3y - 9 + 3

x     = 3y - 6 .......................................... equation 1

In five years time

father = x + 5

son = y + 5

Then , from the second statement

x + 5 = 2 ( y + 5 )

x + 5 = 2y + 10

x       = 2y + 10 - 5

x       = 2y + 5 ........................ equation 2

Equating equation 1 and 2 , we have

3y -6 = 2y + 5

add 6 to both sides

3y = 2y + 5 + 6

subtract 2y from both sides

3y - 2y = 11

y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4      = 15

sum of their ages in four years time will be

31 + 15 = 46 years

5 0
3 years ago
Read 2 more answers
Pleas help me I need help really bad Which shows the given inequalities in slope-intercept
gayaneshka [121]

Answer:

the answer is B

Step-by-step explanation:

8 0
3 years ago
Use distributive property. 4 x 63 = ??
aleksandrvk [35]

Answer:

(4) * (63)

252

(* ̄3 ̄)╭

4 0
3 years ago
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
Yes, a binary tree can be a maxheap. Consider a binary search tree with two values 3 and 5, where 5 is at the root. The tree is
Alchen [17]

Answer:

3 and 5

Step-by-step explanation:

factor tree is more appropriate.

4 0
3 years ago
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