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3 years ago

What is 3(x-5)-14=2(x-7)+2

Mathematics

1 answer:

Evgen [1.6K]3 years ago

5 0

Answer: x = 7

Step-by-step explanation:

To solve the equation,

First step, open the bracket

3(x-5)-14=2(x-7)+2

3x -15 -14 = 2x -14 +2

Then, add the like terms

3x - 29 = 2x -16

Transpose the values at the right hand side to the left hand side

3x - 2x = -16 + 29

x = 7

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Whitepunk [10]

Since the exponent is on the outside of the paranthesis, you'd have to multiply it by everything on the inside: a^m x b^m

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3 years ago

Hello, can you please express this without denominators with the work?

Lena [83]

$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
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-----------------------------\\\\
\cfrac{4xy}{mn^5}\implies \cfrac{4xy}{1}\cdot \cfrac{1}{m^1}\cdot \cfrac{1}{n^5}\implies 4xym^{-1}n^{-5}$

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3 years ago

What is 4/5 * 7/9. Ik It’s easy but I don’t feel like doing it ;)

valina [46]

Answer:

28/45

Step-by-step explanation:

Dont worry i also don't feel like doing fractions most the time they can get very annoying when you have to work with a lot of them.

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2 years ago

Read 2 more answers

Let L be a tangent line to the hyperbola x y = 2 at x = 9 . Find the area of the triangle bounded by L and the coordinate axes.

mafiozo [28]

Answer:

$A = 4$

Step-by-step explanation:

The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:

$y = \frac{2}{x}$

$y'=-2\cdot x^{-2}$

The numerical value of the slope is:

$y' = -2 \cdot (9)^{-2}\\y' = -\frac{2}{81}$

The component of the y-axis is:

$y = \frac{2}{9}$

Now, the tangent line has the following mathematical model:

$y = m \cdot x + b$

The value of the intercept is found by isolating it within the equation and replacing all known variables:

$b = y - m \cdot x$

$b = \frac{2}{9}-(-\frac{2}{81} )\cdot (9)\\b = \frac{4}{9}$

Thus, the tangent line is:

$y = -\frac{2}{81}\cdot x + \frac{4}{9}$

The vertical distance between a point of the tangent line and the origin is given by the intercept.

$d_{y} = \frac{4}{9}$

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:

$-\frac{2}{81}\cdot x + \frac{4}{9}=0$

$-\frac{2}{9}\cdot x + 4 = 0$

$x = 18$

$d_{x} = 18$

The area of the triangle is computed by this formula:

$A = \frac{1}{2}\cdot d_{x}\cdot d_{y}$

$A = \frac{1}{2}\cdot (18)\cdot (\frac{4}{9} )$

$A = 4$

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3 years ago

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AfilCa [17]

Answer:

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3 years ago