Answer:
(3.5, 3) and (0,-4)
Step-by-step explanation:
Zeros are the points that are on the x-intercept. The points not on the x-intercept are (3.5, 3) and (0,-4)
these inequalities can be solved just like equations
a. x - 7 > 25
+ 7 +7 x > 32the number line would have a filled in circle at 32 with an arrow pointing to the rightb. x - 8 < 5+8 +8x < 13 the number line would have an empty circle at 13 with an arrow pointing to the leftc.x + 11 > 23 - 11 - 11x > 12the number line would have an empty circle at 12 with an arrow pointing to the rightd. x + 12 < 6 - 12 - 12 x < -6the number line would have a filled in circle at -6 with an arrow pointing to the lefta. 21 < x + 18 -18 -18 3 < xx > 3b. 16 < x - 7 + 7 + 7 23 < x x > 23c. 12 > x - 7 + 7 + 7 19 > x x < 19d. 29 < x + 53 - 53 - 53 -24 < x x > -24e. 15 > x + 19 -19 -19 -4 > x x < -4f. 35 > x - 8 +8 +8 43 > x x < 43g. -6 < x - 18 +18 +18 12 < x x > 12h. -15 < x - 2 + 2 +2 -13 < x x > -13
Answer:
x = 2 and x = 10
Step-by-step explanation:
(x+3)^2 = (x - 5)^2 + (x + 2)^2
x^2 + 6x + 9 = x^2 - 10x + 25 + x^2 + 4x + 4
x^2 + 6x + 9 =2x^2 - 6x + 29
x^2 - 12x + 20 = 0
(x - 10)(x - 2) = 0
x - 10 = 0; x = 10
x - 2 = 0; x = 2