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MArishka [77]
3 years ago
13

Whats the upper bound for estimate for 354 + 267?

Mathematics
1 answer:
quester [9]3 years ago
7 0

Personally I'd replace 354 with 360 and 267 with 270, and then add 360 and 270, obtaining 630.  Similarly, estimate 63.75 + 3.63 by adding 60 and 3:  63.  There's no single answer for either problem.  For "upper bound," I round the given addends upward; for "lower bound," I found the addends down.

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Halloween Candy Halloween is Kelly's favorite holiday of the year! Based on experience, Kelly knows that on average, each house
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Using the <u>normal distribution and the central limit theorem</u>, it is found that there is an approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

Normal Probability Distribution

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for n instances of a normal variable, the mean is n\mu while the standard deviation is s = \sigma\sqrt{n}.

In this problem:

  • Mean of 4 candies, hence \mu = 4.
  • Standard deviation of 1.5 candies, hence \sigma = 1.5.
  • She visited 35 houses, hence n = 35, \mu = 35(4) = 140, s = 1.5\sqrt{4} = 3

The probability is the <u>p-value of Z when X = 122</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{122 - 140}{3}

Z = -6

Z = -6 has a p-value of 0.

Approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

A similar problem is given at brainly.com/question/24663213

6 0
3 years ago
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