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Ronch [10]
3 years ago
9

A group of family went to the store and bought burgers. The first family bought 4 hamburger and 3 cheeseburger for $31. The seco

nd family bought 3 hamburger and 2 cheeseburger for $22. What is the price for each. Let O be the price of hamburger and P be cheeseburger.
Mathematics
1 answer:
den301095 [7]3 years ago
4 0
4 hamburgers + 3 cheeseburgers = $31 --------------------- (1)
3 hamburgers + 2 cheeseburgers = $22 --------------------- (2)

(1) x 3 : 12 hamburgers + 9 cheeseburgers = $93 --------------------- (1a)
(2) x 4 : 12 hamburgers + 8 cheeseburgers = $88 --------------------- (2a)

(2a) - (1a) :1 cheeseburger = $5 --------------------- sub into equation (1)

4 hamburgers + 3 ($5) = $31 
4 hamburgers + $15 = $31 
4 hamburgers + $15 = $31 
4 hamburgers = $16

1 hamburger = $16 ÷ 4 
1 hamburger = $4

Answer : 1 hamburger = $4 and 1 cheeseburger = $5 
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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:x = -\cfrac{4}{15}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: 6x - 5 =  - 9x - 9

[ add 9x and 5 on both sides ]

\qquad \tt \rightarrow \: 6x - 5 + 9x + 5 =  - 9x - 9 + 9x + 5

\qquad \tt \rightarrow \: 6x + 9x =  - 9 + 5

\qquad \tt \rightarrow \: 15x = -  4

\qquad \tt \rightarrow \: x =  -  \cfrac{4}{15}

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