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3 years ago

Find the solution: 2x=(360/4)

1 answer:

6 0

The correct answer for this question is "45."

Based from the equation that is shown
2x = (360 / 4)

First, we need to simplify 360 / 4 (if it can be simplified).
So we get,

2x = 90

Then, Multiply both sides by (1/2) leaving x behind.
(1/2) * 2x = (1/2) * 90
x = 45

so the value of x is 45.

You might be interested in

What is the missing constant term in the perfect square that starts with x^2+2x?

Natasha_Volkova [10]

Answer:

+ 1

Step-by-step explanation:

Given

x² + 2x

Using the method of completing the square

add ( half the coefficient of the x- term)² to x² + 2x

= x² + 2(1)x + 1²

= x² + 2x + 1

= (x + 1)² ← perfect square

4 0

3 years ago

Solve for g.<br> -3+5+6g=11-3g−3+5+6g=11−3g

PtichkaEL [24]

Answer: $\mathrm{No\:Solution}$

Step-by-step explanation:

$\begin{bmatrix}-3+5+6g=1\\ 1-3g+5+6g=11-3g\end{bmatrix}$

$\begin{bmatrix}1-3\left(-\frac{1}{6}\right)+5+6\left(-\frac{1}{6}\right)=11-3\left(-\frac{1}{6}\right)\end{bmatrix}$

$\begin{bmatrix}\frac{11}{2}=\frac{23}{2}\end{bmatrix}$

$\frac{11}{2}=\frac{23}{2}\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}$

4 0

3 years ago

According to a random sample taken at 12 A.M., body temperatures of healthy adults have a bell-shaped distribution with a mean

mrs_skeptik [129]

Answer:

There are 89% of healthy adults with body temperatures that are within 3 standard deviations of the mean

The minimum value that is within 3 standard deviations of the mean is 96.57.

The maximum value that is within 3 standard deviations of the mean is 100.11.

Step-by-step explanation:

Chebyshev's theorem states that a minimum of 89% of the values lie within 3 standard deviation of the mean.

Using Chebyshev's theorem, what do we know about the percentage of healthy adults with body temperatures that are within 3 standard deviations of the mean?

There are 89% of healthy adults with body temperatures that are within 3 standard deviations of the mean.

What are the minimum and maximum possible body temperatures that are within 3 standard deviations of the mean?

We have that the mean $\mu$ is 98.34 and the standard deviation $\sigma$ is 0.59. So:

Minimum

$Mi = \mu - 3\sigma = 98.34 - 3(0.59) = 96.57$

Maximum

$Ma = \mu + 3\sigma = 98.34 + 3(0.59) = 100.11$

8 0

3 years ago

Need help with problem, been stuck on it for a while

Alinara [238K]

Well, if you look at the picture, the "radius" is 1/4, so r = 1/4.

$\bf \textit{diameter of a circle}\\\\
d= 2r\qquad \boxed{r=\frac{1}{4}}\implies d=2\cdot \cfrac{1}{4}\implies d=\cfrac{1}{2}\\\\
-------------------------------\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies C=2\left( \frac{22}{7} \right)\left( \frac{1}{4} \right)
\\\\\\
C=\cfrac{2\cdot 22\cdot 1}{7\cdot 4}\implies C=\cfrac{11}{7}\\\\
-------------------------------\\\\$

$\bf \textit{area of a circle}\\\\
A=\pi r^2\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies A=\left( \frac{22}{7} \right)\left( \frac{1}{4} \right)^2
\\\\\\
A=\cfrac{22}{7}\cdot \cfrac{1^2}{4^2}\implies A=\cfrac{22}{7}\cdot \cfrac{1}{16}\implies A=\cfrac{11}{56}$

8 0

4 years ago

Solve the equation for a k=4a

nata0808 [166]

Answer: a = $\frac{K}{4+9b}$

Step-by-step explanation:

Rewrite the equation as 4a + 9ab=K

Factor out a of 4a + 9b

a (4 + 9b) = K

divide each term by 4 + 9b and simplify

= $\frac{K}{4+9b}$

7 0

3 years ago