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4 years ago

Solve for n: 2n+3=-3.2

Mathematics

2 answers:

REY [17]4 years ago

7 0

Answer:

2n+3=3.2

2n=3.2-3

2n=0.2

n=0.2/2

n=0.1

dem82 [27]4 years ago

6 0

You start by subtaravting 3

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Tracy deposited $59 into a bank account that earned 3.5% simple interest each year. If no money was deposited into or withdrawn

Illusion [34]

Answer

Find out the how much money was in the account after $1\frac{1}{2}$ years.

To prove

Formula

$Simple\ interest = \frac{Principle\times Rate\times time}{100}$

As given

Tracy deposited $59 into a bank account that earned 3.5% simple interest each year.

Principle = $59

Rate = 3.5 %

$Time = 1\frac{1}{2}$

i.e

$Time = \frac{3}{2}$

Time = 1.5 years

Put all the values in the equation

$Simple\ interest = \frac{59\times 3.5\times 1.5}{100}$

= \frac{309.75}{100}[/tex]

= $3.1(approx)

Amount in the account = Principle + Simple interest

= $59 + $ 3.1

= $ 62.1

1 Dollar = 100 cent

Now convert $62.1 into cent.

= 62.1 × 100

= 6210 cent

Therefore the money in the account is 6210 cent .

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4 years ago

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A line includes the points (10, 4) and (0, 2). What is its equation in slope-intercept form?

alukav5142 [94]

Answer:

Slope is 1/5 and equation is 4-2 / 10-0

Step-by-step explanation:

Its equation is 4-2 / 10-0

-2/-10 = 1/5 Slope is 1/5

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3 years ago

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What is 2/5 ÷ 6/8 please

Alchen [17]

The First Answer is 0.4 and the second answer is 0.75.

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3 years ago

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Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which

Marizza181 [45]

Answer:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=10$ represent the sample standard deviation

n represent the sample size

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (3) we got:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

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koban [17]

Answer:

230/84 = 63.9/25

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3 years ago