He bought 3 small notebooks (3*7=21) and 3 large notebooks (3*10=30)
21+30=51
Answer:
a,480 over 60=80cm3
b,(c over 24)the whole cubed=480 over 60
c*60=24*480
c=11520/60
=192
1.) 14
2.) 10
3.) 7 : 6
5.) 80
6.) 8 : 7
these are all i have the time to answer i'm sorry!
Answer:
Step-by-step explanation:
Following changes will be there when the figure is transformed by the given rules.
1). Rule for transformation has been given as,
(x, y) → (x, -y)
Reflection across x axis.
2). (x, y) → (-x, -y)
Rotation of 180° about the origin.
3). (x, y) → (x - 4, y)
Shifted 4 units left horizontally.
4). (x, y) → (x, y + 3)
Shifted vertically up by 3 units
5). (x, y) → (x - 1, y + 4)
Shifted 1 units left horizontally and 4 units up vertically.
6). (x, y) → (4x, 4y)
Dilated by 4 units.
LORAN follows an hyperbolic path.
The equation of the hyperbola is: ![\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7Bx%5E2%7D%7B2500%7D%20%2B%20%5Cfrac%7By%5E2%7D%7B1100%7D%20%3D%201%7D)
The coordinates are given as:
![\mathbf{(x,y) = (-60,0)\ (60,0)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28x%2Cy%29%20%3D%20%28-60%2C0%29%5C%20%2860%2C0%29%7D)
The center of the hyperbola is
![\mathbf{(h,k) = (0,0)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28h%2Ck%29%20%3D%20%280%2C0%29%7D)
The distance from the center to the focal points is given as:
![\mathbf{c = 60}](https://tex.z-dn.net/?f=%5Cmathbf%7Bc%20%3D%2060%7D)
Square both sides
![\mathbf{c^2 = 3600}](https://tex.z-dn.net/?f=%5Cmathbf%7Bc%5E2%20%3D%203600%7D)
The distance from the receiver to the transmitters is given as:
![\mathbf{2a = 100}](https://tex.z-dn.net/?f=%5Cmathbf%7B2a%20%3D%20100%7D)
Divide both sides by 2
![\mathbf{a = 50}](https://tex.z-dn.net/?f=%5Cmathbf%7Ba%20%3D%2050%7D)
Square both sides
![\mathbf{a^2 = 2500}](https://tex.z-dn.net/?f=%5Cmathbf%7Ba%5E2%20%3D%202500%7D)
We have:
![\mathbf{b^2 = c^2 - a^2}](https://tex.z-dn.net/?f=%5Cmathbf%7Bb%5E2%20%3D%20c%5E2%20-%20a%5E2%7D)
This gives
![\mathbf{b^2 = 3600 - 2500}](https://tex.z-dn.net/?f=%5Cmathbf%7Bb%5E2%20%3D%203600%20-%202500%7D)
The equation of an hyperbola is:
![\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7B%28x%20-%20h%29%5E2%7D%7Ba%5E2%7D%20%2B%20%5Cfrac%7B%28y%20-%20k%29%5E2%7D%7Bb%5E2%7D%20%3D%201%7D)
So, we have:
![\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7B%28x%20-%200%29%5E2%7D%7B2500%7D%20%2B%20%5Cfrac%7B%28y%20-%200%29%5E2%7D%7B1100%7D%20%3D%201%7D)
![\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7Bx%5E2%7D%7B2500%7D%20%2B%20%5Cfrac%7By%5E2%7D%7B1100%7D%20%3D%201%7D)
Hence, the equation of the hyperbola is: ![\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7Bx%5E2%7D%7B2500%7D%20%2B%20%5Cfrac%7By%5E2%7D%7B1100%7D%20%3D%201%7D)
Read more about hyperbolas at:
brainly.com/question/15697124